LeetCode 1394. Find Lucky Integer in an Array
The Problem
Link to original problem on Leetcode.
Given an array of integers arr
, a lucky integer is an integer which has a frequency in the array equal to its value.
Return a lucky integer in the array. If there are multiple lucky integers return the largest of them. If there is no lucky integer return -1
.
Examples
Example 1:
Input: arr = [2,2,3,4]
Output: 2
Explanation: The only lucky number in the array is 2 because frequency[2] == 2.
Example 2:
Input: arr = [1,2,2,3,3,3]
Output: 3
Explanation: 1, 2 and 3 are all lucky numbers, return the largest of them.
Example 3:
Input: arr = [2,2,2,3,3]
Output: -1
Explanation: There are no lucky numbers in the array.
Example 4:
Input: arr = [5]
Output: -1
Example 5:
Input: arr = [7,7,7,7,7,7,7]
Output: 7
Constraints
1 <= arr.length <= 500
1 <= arr[i] <= 500
My Solution
This solution creates a Map of the integer values in arr
along with their count. It then iterates over the Map, comparing keys and values for equality. An initial result
of -1
is then replaced if a lucky integer is found, and any larger lucky integer will in turn replace a smaller one. This takes time.
const findLucky = arr => {
const integers = new Map();
let result = -1;
arr.forEach(i => {
if (!integers.has(i)) {
integers.set(i, 1);
} else {
integers.set(i, 1 + integers.get(i));
}
});
for ([key, value] of integers) {
if (key === value && key > result) {
result = key;
}
}
return result;
};