# 283. Move Zeroes

## The Problem

Link to original problem on Leetcode.

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

Example:

Input: [0,1,0,3,12]
Output: [1,3,12,0,0]


Note:

1. You must do this in-place without making a copy of the array.
2. Minimize the total number of operations.

## My Solution

This $O(n)$ time solution uses two variables, i and j, in a for loop. The first, i, is used to actually count iterations and stop before hitting the array's length. The second, j, keeps track of which index in the constantly mutating nums array you're currently looking at.

Every time nums[j] is a 0, it gets spliced out and pushed to the end. Everything that was after nums[j] will shift ahead by 1 index value, so j is decremented by 1 to make sure we're look at what came after that 0 instead of what was two places after it. After i iterations, we can safely assume we've checked the entire nums array.

const moveZeroes = function(nums) {    for (let i = 0, j = 0; i < nums.length; i++, j++) {        if (nums[j] === 0) {            nums.push(nums.splice(j, 1));            j--;        }    }};